SOLUTION: What are the coordinates of points Q and R where Q is on {{{ y=(1/2)x-2 }}} and R is on {{{ y= -x+5 }}} and a line is drawn from P to intersect with the lines so that P is the midp

Algebra ->  Length-and-distance -> SOLUTION: What are the coordinates of points Q and R where Q is on {{{ y=(1/2)x-2 }}} and R is on {{{ y= -x+5 }}} and a line is drawn from P to intersect with the lines so that P is the midp      Log On


   



Question 896575: What are the coordinates of points Q and R where Q is on +y=%281%2F2%29x-2+ and R is on +y=+-x%2B5+ and a line is drawn from P to intersect with the lines so that P is the midpoint of QR and P(1,1)
Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
We let the x-component of Q be a, Then since Q is on the line
y=expr%281%2F2%29x-2, the y-component of Q is found by substituting
a for x in y=expr%281%2F2%29x-2 and get y=expr%281%2F2%29a-2. So
Q is the point Q(a,expr%281%2F2%29a-2),

We let the x-component of R be b, Then since R is on the line
y=-x%2B5, the y-component of R is found by substituting
b for x in y=-x%2B5 and get y=-b%2B5. So
R is the point R(b,-b+5)



We are told that P(1,1) is the midpoint of QR.  We use the
midpoint formula:

Midpoint = 

Midpoint = 

So we equate those coordinates to the coordinates of P(1,1).

Equating the x-coordinates of P

%28a%2Bb%29%2F2=1
a%2Bb=2

Equating the y-coordinates of P

%28%28expr%281%2F2%29a-2%29%2B%28-b%2B5%29%29%2F2=1
%28expr%281%2F2%29a-2%29%2B%28-b%2B5%29=2
expr%281%2F2%29a-2-b%2B5=2
expr%281%2F2%29a-b%2B3=2
Multiply through by 2:
a-2b%2B6=4
a-2b=-2

So we solve the system by substitution or elimination:

system%28a%2Bb=2%2Ca-2b=-2%29
Solve the first for a=2-b
Substitute in the second equation:
(2-b)-2b=-2
  2-b-2b=-2
    2-3b=-2
     -3b=-4
       b=4%2F3

a=2-b
a=2-4%2F3
a=6%2F3-4%2F3
a=2%2F3

So the point Q%28a%2Cexpr%281%2F2%29a-2%29%29 becomes:

Q%282%2F3%2Cexpr%281%2F2%29%282%2F3%29-2%29%29

Q%282%2F3%2C1%2F3-2%29%29

Q%282%2F3%2C1%2F3-6%2F3%29%29

Q%282%2F3%2C-5%2F3%29%29

So the point R(b,-b+5) becomes:

R%284%2F3%2C-4%2F3%2B5%29

R%284%2F3%2C-4%2F3%2B15%2F3%29

R%284%2F3%2C11%2F3%29

Edwin