SOLUTION: i am needing help on the following (12x^7)(16x^9)=2*2*2*3*3*x^7*x^9 (3x^9)(16x) =3*2*2*2*2*x^9*x This is a fraction I am not sure how they got the first terms factored down

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: i am needing help on the following (12x^7)(16x^9)=2*2*2*3*3*x^7*x^9 (3x^9)(16x) =3*2*2*2*2*x^9*x This is a fraction I am not sure how they got the first terms factored down       Log On


   



Question 896562: i am needing help on the following
(12x^7)(16x^9)=2*2*2*3*3*x^7*x^9
(3x^9)(16x) =3*2*2*2*2*x^9*x
This is a fraction I am not sure how they got the first terms factored down to what is on the right side of the = sign
Please help

Found 2 solutions by Alan3354, MathTherapy:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
i am needing help on the following
(12x^7)(16x^9)=2*2*2*3*3*x^7*x^9
(3x^9)(16x) =3*2*2*2*2*x^9*x
This is a fraction I am not sure how they got the first terms factored down to what is on the right side of the = sign
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I'm not sure either.
(12x^7)(16x^9)=2*2*2*3*3*x^7*x^9 is not true.
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Also, help with what?
What do you want to do?

Answer by MathTherapy(10555) About Me  (Show Source):
You can put this solution on YOUR website!
i am needing help on the following
(12x^7)(16x^9)=2*2*2*3*3*x^7*x^9
(3x^9)(16x) =3*2*2*2*2*x^9*x
This is a fraction I am not sure how they got the first terms factored down to what is on the right side of the = sign
Please help

%2812x%5E7%29%2816x%5E9%29+=+2%2A2%2A2%2A3%2A3%2Ax%5E7%2Ax%5E9
%283x%5E9%29%2816x%29++++=+3%2A2%2A2%2A2%2A2%2Ax%5E9%2Ax
What you have to the right of the equals sign are the PRIME FACTORS of each NUMBER, and the product of the variables.
For example, the PRIME FACTORS of 12 are: 2, 2, and 3, while the PRIME FACTORS of 16 are: 2, 2, 2, and 2.
However, %2812x%5E7%29%2816x%5E9%29 is INCORRECT, and should be: %2812x%5E7%29%2816x%5E9%29+=+2%2A2%2A2%2A2%2A2%2A2%2A3%2Ax%5E7%2Ax%5E9