IN AN ELECTION BETWEEN A AND B 360 PEOPLE VOTED, A WON. NEXT YEAR B INCREASED HIS VOTES BY 37.5% AND WON BY DOUBLE THE MAJORITY OF A. HOW MANY VOTES B GOT IN FIRST ELECTION?
Let number of votes B received in 1st election, be B
Then A received: 360 - B votes
Number of votes that A won by (1st election): 360 - B B, or 360 2B
In 2nd election, B increased his number of votes by 37.5%, which means B received 1.375B votes,
in the 2nd election
Since B doubled the number of votes that A had won by in the 1st election, then B won by:
2(360 2B), or 720 4B votes
Number of votes A received in 2nd election, plus amount of votes B received in 2nd election, equals total votes cast
Number of votes A received in 2nd election: 1.375B
Number of votes B received in 2nd election: 1.375B (720 4B), or 1.375B 720 + 4B, or 5.375B 720
Number of votes cast in 2nd election: 360 (same as 1st)
Thus, we get: 1.375B + (5.375B 720) = 360
1.375B + 5.375B 720 = 360
1.375B + 5.375B = 360 + 720
6.75B = 1,080
B, or number of votes B received in 1st election = 
, or 
You can do the check!!
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