Question 895757: The length of a rectangular room is 3m more than 2 times its width. If the perimeter is 30 m, how wide is the room?
Please help, i got really stuck on it.
Found 2 solutions by josgarithmetic, MathTherapy: Answer by josgarithmetic(39617) (Show Source): Answer by MathTherapy(10552) (Show Source):
You can put this solution on YOUR website! The length of a rectangular room is 3m more than 2 times its width. If the perimeter is 30 m, how wide is the room?
Please help, i got really stuck on it.
Let width be W
Then length, or L = 2W + 3 ----- eq (i)
Since 2(W + L) = perimeter, then: 2(W + L) = 30____2(W + L) = 2(15)_____W + L = 15 ------- eq (ii)
W + 2W + 3 = 15 ------- Substituting 2W + 3 for L in eq (ii)
3W + 3 = 15
3W = 12
W, or width = , or m
You can do the check!!
Send comments, “thank-yous,” and inquiries to “D” at MathMadEzy@aol.com.
Further help is available, online or in-person, for a fee, obviously.
For FREE info and answers to questions about the ASVAB exam, the NYS 3 – 8 city/state wide exams,GENERAL
MATH and HOMEWORK QUESTIONS, or MATH QUESTIONS related to the Regents Integrated Algebra,
Regents Geometry, Regents Algebra 2/Trigonometry, SHSAT, COOP/HSPT/TACHS, PSAT, SAT, ACT, SSAT/ISEE,
GRE, CLEP, and the TASC/GED, you can visit: http://asvabstudyzone.freeforums.net/.
|
|
|