SOLUTION: log base 2 (log base 3 (log base 5 of x)) = 0

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Question 895678: log base 2 (log base 3 (log base 5 of x)) = 0
Found 2 solutions by stanbon, MathTherapy:
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
log base 2 (log base 3 (log base 5 of x)) = 0
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log2[log3(log(x)/log(5)) = 0
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log2[log[log(x)/log(5)]/log(3)] = 0
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log[log[log[log(x)/(log(5)*log(3))]/(log(2)) = 0
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log[log[log(x)/(log(5)*log(3)*log(2))] = 0
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log[log(x)/(log(5)*log(3)*log(2))] = 1
log(x)/(log(5)(log(3)*log(2))/ = 10
log(x) = 10*log(5)*log(3)(log(2))
log(x) = 1.0039
x = 10*1.0039
x = 10.0906
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Cheers,
Stan H.
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Answer by MathTherapy(10699) (Show Source):
You can put this solution on YOUR website!

log base 2 (log base 3 (log base 5 of x)) = 0 ============================================= The answer is NOT x = 10.0906, as the other person states, and this equation is not solved the way he did! log base 2 (log base 3 (log base 5 of x)) = 0 happens to be: