Question 895641: Fred begins walking toward John's house at 3 miles per hour. John leaves his house at the same time and walks toward Fred's house on the same path at a rate of 2 miles per hour. How long will it be before they meet if the distance between the house is 4 miles.
Tried to set up a table with rate, distance, speed, and time. Not sure how to set up equation and solve.
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! Fred begins walking toward John's house at 3 miles per hour.
John leaves his house at the same time and walks toward Fred's house on the same path at a rate of 2 miles per hour.
How long will it be before they meet if the distance between the houses is 4 miles.
:
let t = the walking time of the two boys (in hrs)
:
When they meet, they will have traveled a total of 4 mi
Write a distance equation dist = speed * time
Fred's dist + John's dist = 4 mi
3t + 2t = 4
5t = 4
t = 4/5 hr or .8(60) = 48 min
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