SOLUTION: {{{(x+3)^2=-8(y-5)}}}. How do I find P for this problem? I know that its from the translated form of the vertical axis of symmetry which is (x-h)^2=4p(y-k). I remember my teache

Algebra ->  Trigonometry-basics -> SOLUTION: {{{(x+3)^2=-8(y-5)}}}. How do I find P for this problem? I know that its from the translated form of the vertical axis of symmetry which is (x-h)^2=4p(y-k). I remember my teache      Log On


   

Question 895256: %28x%2B3%29%5E2=-8%28y-5%29.
How do I find P for this problem? I know that its from the translated form of the vertical axis of symmetry which is (x-h)^2=4p(y-k).
I remember my teacher saying something about multiply and divide by 4 but I don't remember how he said to do it.
Please help!
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
%28x%2B3%29%5E2=-8%28y-5%29.
How do I find P for this problem? I know that its from the translated form of the vertical axis of symmetry which is (x-h)^2=4p(y-k).
***
Given equation is that of a parabola which opens downward.
Its basic form of equation:
(x-h)^2=-4p(y-k), (h,k)=coordinates of vertex)(Don't forget the minus sign)
For given equation:(x+3)^2=-8(y-5)
4p=|-8|=8
p=2