SOLUTION: 3 square root of 27k to the ninth power
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Question 89517
This question is from textbook
intermediate algebra
:
3 square root of 27k to the ninth power
This question is from textbook
intermediate algebra
Answer by
stanbon(75887)
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3 square root of 27k to the ninth power
--------
3sqrt(27k^9)
= 3sqrt(9k^8)sqrt(3k)
= 3*3*k^4 sqrt(3k)
= 9k^4 sqrt(3k)
===================
Cheers,
Stan H.