SOLUTION: A lot is in the shape of a rectangle with a perimeter of 66 meters. The length is 4 meters less than twice the width. Find the length.
I need help setting this up please. I have
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-> SOLUTION: A lot is in the shape of a rectangle with a perimeter of 66 meters. The length is 4 meters less than twice the width. Find the length.
I need help setting this up please. I have
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Question 895138: A lot is in the shape of a rectangle with a perimeter of 66 meters. The length is 4 meters less than twice the width. Find the length.
I need help setting this up please. I have attempted to set up the equation below but when I plug in the numbers I am missing something. Thank you.
Length= 4 meters - 2x (x)
width= x
perimeter = 66 meters Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! A lot is in the shape of a rectangle with a perimeter of 66 meters. The length is 4 meters less than twice the width. Find the length.
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let x=width
2x-4=length
2(length+width)=perimeter
2(2x-4+x)=66
6x-8=66
6x=74
x=74/6=37/3
2x-4=(2*37/3)-4=74/3-4=74/3-12/3=62/3
length=62/3 meters
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