SOLUTION: I just need help setting up the equation. It's from Algebra, Part 3 from Thomson Education Direct. It's a career oriented study unit. # of book is 2469C-1 A person travels 4 hrs

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Question 89511: I just need help setting up the equation. It's from Algebra, Part 3 from Thomson Education Direct. It's a career oriented study unit. # of book is 2469C-1
A person travels 4 hrs by plane and 25 hrs by ship and covers a total distance of 1580 miles. If the plane's speed would have been 1/2 of the actual speed and the ship's speed 1/4 greater than the actual speed, a distance of 1315 miles would have been travelled. Find the speeds of the plane and the ship.

Found 2 solutions by scott8148, ankor@dixie-net.com:
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
rate*time=distance ... p equals plane speed, s equals ship speed ... 4p+25s=1580 ... 4(p/2)+25(s(5/4))=1315

here are the equations ... let me know if you need help with the solution

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
A person travels 4 hrs by plane and 25 hrs by ship and covers a total distance of 1580 miles. If the plane's speed would have been 1/2 of the actual speed and the ship's speed 1/4 greater than the actual speed, a distance of 1315 miles would have been traveled. Find the speeds of the plane and the ship.
:
Let x = actual speed of the plane; and: y = actual speed of the ship
:
Write 2 distance equations; Dist = time * speed:
:
4x + 25y = 1580; actual speed equation
:
We also have:
"If the plane's speed would have been 1/2 of the actual speed and the ship's speed 1/4 greater than the actual speed, a distance of 1315 miles "
:
Equation for this would be:
1%2F2%29*4x + 5%2F4*25y = 1315
:
Mult equation by 4 to get rid of these fractions and we have:
2(4x) + 5(25y) = 5260
:
8x + 125y = 5260; the "if..." equation
:
Multiply the actual equation by 2 and subtract it from the above equation
8x + 125y = 5260
8x + 50y = 3160
---------------- subtraction eliminates x
0x + 75y = 2100
y = 2100/75
y = 28 mph is the ships speed
:
Use the actual speed equation to find x
4x + 25(28) = 1580
4x + 700 = 1580
4x = 1580 - 700
4x = 880
x = 880/4
x = 220 mph is the speed of the plane
:
Check solutions in the "if.." equation
1%2F2%29*4(220) + 5%2F4*25(28) = 1315
:
440 + 875 = 1315
;
:
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