Question 894668: 1+(1/x^2)=(3/x)
what are the solutions to the equation?
A. x=(3/2)+(square root of 5/2); x=(3/2)-(square root of 5/2)
B.x=(3)+(square root of 5/2); x=(3)-(square root of 5/2)
C.x=(3/2)+(square root of 13/2); x=(3/2)-(square root of 13/2)
D.x=(3)+(square root of 13/2); x=(3)-(square root of 13/2)
i get most of how to do it but im messing up which getting the answer im not getting one of these a, b, c, d
Answer by KMST(5328)   (Show Source):
You can put this solution on YOUR website! Maybe the results you are getting are the same as one of the options, but expressed in an equivalent form.
There are many ways to solve the equation.
I would start by multiplying both sides of the equal sign times  ,
and then I would solve the resulting quadratic equation:
One way to solve that quadratic equation is by completing the square>
Since  is part of the square  ,
we can complete the square by adding  .
of course, we add it to both sides of the equation, to get an equivalent equation:
 --->  by using the quadratic formula,
which says that the solutions to  are given by  .
In the case of ,  ,  , and  , so
 ,
 ,
 .
That is the same as
 , which is a way of saying 
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