SOLUTION: Would someone help me please.
The directions are to divide. x^3+2x^2+x+12/x+3. I have four choices for the answer A)x^2-x+4, B)x^2+x-14, C) x^2-x-4, and D) x^2+x-4.
Please show
Algebra ->
Quadratic Equations and Parabolas
-> SOLUTION: Would someone help me please.
The directions are to divide. x^3+2x^2+x+12/x+3. I have four choices for the answer A)x^2-x+4, B)x^2+x-14, C) x^2-x-4, and D) x^2+x-4.
Please show
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Question 89456: Would someone help me please.
The directions are to divide. x^3+2x^2+x+12/x+3. I have four choices for the answer A)x^2-x+4, B)x^2+x-14, C) x^2-x-4, and D) x^2+x-4.
Please show me step by step how you got this answer, and what method or formula you used to solve? Thank you Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! x^3+2x^2+x+12/x+3
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Using synthetic division:
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-3)....1....2....1....12
........1....-1....4..|..0
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Remainder: 0
Quotient: x^2-x+4
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Cheers,
Stan H.
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