SOLUTION: Please help me on how to figure out the y-intercept of the graph of the equation y=x2 (this is x squared) 6x = 9 and -3/2 (x-6)2 (squared).

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Please help me on how to figure out the y-intercept of the graph of the equation y=x2 (this is x squared) 6x = 9 and -3/2 (x-6)2 (squared).      Log On


   

Question 89453: Please help me on how to figure out the y-intercept of the graph of the equation y=x2 (this is x squared) 6x = 9 and -3/2 (x-6)2 (squared).
Found 2 solutions by checkley75, stanbon:
Answer by checkley75(3666) About Me  (Show Source):
You can put this solution on YOUR website!
y=x^2 (red line)
+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+y+=+x%5E2%29+ (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y = x^2 ).
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6x=9 or x=9/6 or x=1.5 this line has no y intercept. it is a verticle line passing through (1.5,0)
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-3/2(x-6)^2 also has no y intercept
-3/2(x^2-12x+36) or -3x^2-18x-54 or -3(x^2+6x+18)

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
figure out the y-intercept of the graph of the equation y=x2 (this is x squared) 6x = 9 and -3/2 (x-6)2 (squared).
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Do you mean y = x^2+6x+9 and y=(-3/2)(x-6)^2
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Cheers,
Stan H