SOLUTION: Please help me solve this: 8/3 t + 1 > -5 I have: 8/3 t > -6 t > -18/8 t > -9/4

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Question 894262: Please help me solve this: 8/3 t + 1 > -5
I have:
8/3 t > -6
t > -18/8
t > -9/4
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
If the problem is 8%2F3t%2B1%3E-5 , you solved it.
-9%2F4=-2.25 and we can graph that value on a number line.
number_line%28+600%2C+-10%2C+10%2C+-2.25%29
All the numbers to the right of -9%2F4 on the number line are solutions to the equation.
There is an infinite number of them, including fractions like 1%2F2 and -23%2F11 , and fancy numbers like pi .
For easy examples,
t=0 is a solution, because 8%2F3%29%2A0%2B1=1%3E-5 ;
t=-2 is a solution, because 8%2F3%29%2A%28-2%29%2B1=-16%2F3%2B1=-16%2F3%2B3%2F3=-13%2F3=-4%5E1%2F3%3E-5 ,
but t=-3 is not a solution, because 8%2F3%29%2A%28-3%29%2B1=-8%2B1=-7%3C-5 .

However, if your problem was 8%2F%223+t%22%2B1%3E-5 , it is a different story.
You could still write 8%2F%223+t%22%3E-6 , and multiplying times 3%2F8 you would get
1%2Ft%3E-9%2F4 .
From there, I would divide 1=1 by 1%2Ft%3E-9%2F4 to get
1%2F%221+%2F+t%22+%3C1%2F%22-+9+%2F+4%22 ---> t%3C-4%2F9