SOLUTION: Find the equation of the hyperbola which satisfies the given condition center (0,0) conjugate axis along x-axis, one focus at (0,sqrt(13) , equation of one directrix is y = 9sqrt(1

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Find the equation of the hyperbola which satisfies the given condition center (0,0) conjugate axis along x-axis, one focus at (0,sqrt(13) , equation of one directrix is y = 9sqrt(1      Log On


   



Question 894112: Find the equation of the hyperbola which satisfies the given condition center (0,0) conjugate axis along x-axis, one focus at (0,sqrt(13) , equation of one directrix is y = 9sqrt(13)/13
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Find the equation of the hyperbola which satisfies the given condition center (0,0) conjugate axis along x-axis, one focus at (0,sqrt(13) , equation of one directrix is y = 9sqrt(13)/13
***
Given hyperbola has a vertical transverse axis and center at the origin
Its standard form of equation: y%5E2%2Fa%5E2-x%5E2%2Fb%5E2=1
..
y=a/e=a/(c/a)=a^2/c
a^2=c*y=√13*9√13/13=9
c=√13
c^2=13
c^2=a^2+b^2
b^2=c^2-a^2=13-9=4
equation: y%5E2%2F9-x%5E2%2F4=1