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Question 89399: Please help.
Suppose you wanted to design a parabolic arch (a parabola opening downward) as a trellis in your garden. This would mean that the first term of the quadratic equation, the term with the variable raised to the second power, would have to be negative. An engineering friend suggests that the following quadratic function might be aesthetically pleasing.
h(x) = -5x2/64 + 4
This function gives the height of the arch (in feet) at any horizontal distance x (in feet) from the centerline of the arch. The trellis (parabola) could be supported by vertical posts at intervals across the inside of the arch. These posts could be placed at 1, 2, 3, 4, 5, 6, and 7 feet on both sides of the centerline (the axis of the parabola). Therefore, for any distance (x-value) the height of a post supporting the arch at that point could be determined from the above function.
1. When drawing the graph of this parabola, where is its axis located in the coordinate plane?
2. Where would the arch touch the ground? (i.e. How far from the axis of the parabola?)
Answer by scott8148(6628)   (Show Source):
You can put this solution on YOUR website! 1. the function has no x term (as opposed to x^2) so the axis of symmetry is the y-axis
2. the arch touches the ground when h=0, so 0=-5x^2/64+4 ... -4=-5x^2/64 ... -256=-5x^2 ... 51.2=x^2 ... x=+-7.16 (approx.)
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