SOLUTION: divide {{{(3b^2+3b-2)/(b-3)}}}

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Question 893954: divide
%283b%5E2%2B3b-2%29%2F%28b-3%29

Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
3b%5E2%2Fb=3b;

Subtract 3b%28b-3%29 from 3b%5E2%2B3b-2; and decide if this contains any more of b-3 which could be further subtracted.

Answer by MathTherapy(10552) About Me  (Show Source):