SOLUTION: Write the inverse variation equation of the following. Y varies inversely with x and y = 9 when x = 14.

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Write the inverse variation equation of the following. Y varies inversely with x and y = 9 when x = 14.       Log On


   



Question 89393: Write the inverse variation equation of the following. Y varies inversely with x and y = 9 when x = 14.
Answer by bucky(2189) About Me  (Show Source):
You can put this solution on YOUR website!
The "varies inversely with x" means that as x gets bigger, y gets smaller and as x gets smaller,
y gets bigger.
.
This relationship can be written as:
.
y+=+k%2Fx
.
where k is an unknown constant. Notice that as x gets bigger, the denominator of the fraction
on the right gets bigger, so the term on the right gets smaller. Think in terms of x being
10. Then make x bigger, say x = 100. k divided by 10 is bigger than k divided by 100, so
as x gets bigger, the term k divided by x (which equals y) is getting smaller.
.
For this problem you are told that when y is 9, x is 14. So in the equation that contains
k you can substitute 9 for y and 14 for x. When you do that the equation becomes:
.
9+=+k%2F14
.
You can eliminate the denominator on the right side by multiplying both sides by 14 to get:
.
9+%2A+14+=+k
.
Multiply out the left side and the equation becomes:
.
126+=+k
.
Now you can go back to the original equation and substitute 126 for k to get the answer you
are looking for. That answer is that the equation is:
.
y+=+126%2Fx
.
You can check this by letting x = 14 and you will get:
.
y+=+126%2F14+=+9
.
So when x = 14, obviously y = 9. After that you can let x be any value (other than zero
because division by zero is not allowed) and you can calculate the corresponding value
for y. Again, you can let x be two values such as 1 and 100 and you will see that as
x gets bigger, the value of y will vary inversely because it gets smaller.
.
Hope this helps you to understand the problem better.
.