SOLUTION: 2x+4y+4z=42 find the values of x,y & z
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Question 893846
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2x+4y+4z=42 find the values of x,y & z
Answer by
Fombitz(32388)
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To find the value of 3 unknowns you need 3 independent equations, you only have one.
Please repost.
You can always set two values to zero and solve for the third.
(21,0,0)
(0,21/2,0)
(0,0,21/2)