SOLUTION: find two consecutive even integers such that seven more than twice the second is equal to the first

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Question 893562: find two consecutive even integers such that seven more than twice the second is equal to the first
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Two consecutive even integers : N,N%2B2
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7%2B2%28N%2B2%29=N
7%2B2N%2B4=N
2N%2B11=4
2N=-7
N=-7%2F2
There is no solution.
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Looking at the problem setup, double an even integer will get you another even integer but then adding an odd number will produce an odd number not an even number. That's why there's no solution.