SOLUTION: A rectangle is twice as long as it is wide. What is the perimeter if its area is 32 cm2?

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Question 893340: A rectangle is twice as long as it is wide. What is the perimeter if its area is 32 cm2?

Found 2 solutions by algebrahouse.com, josgarithmetic:
Answer by algebrahouse.com(1659) (Show Source):
You can put this solution on YOUR website!
x = width
2x = length {it is twice as long as it is wide}

Area of a rectangle = width x length
x(2x) = 32 {substituted width and length into area formula}
2x� = 32 {multiplied}
x� = 16 {divided each side by 2}
x = 4 {took square root of each side}
2x = 8 {substituted 4, in for x, into 2x}

width = 4 cm
length = 8 cm

Perimeter of a rectangle = 2(width) + 2(length)
= 2(4) + 2(8) {substituted 4 for width and 8 for length}
= 8 + 16 {multiplied}
= 24 {added}

Perimeter = 24 cm

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Answer by josgarithmetic(39617) (Show Source):
You can put this solution on YOUR website!
w for width, L for length, p for perimeter.
, description
, description
, perimeter formula

Solve for w and L.

Evaluate p.