SOLUTION: How many milliliters of pure acid must be added to 150 milliliters of a 30% acid solution to obtain a 40% acid solution

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Question 893132: How many milliliters of pure acid must be added to 150 milliliters of a 30% acid solution to obtain a 40% acid solution
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
How many milliliters of pure acid must be added to 150 milliliters of a 30% acid solution to obtain a 40% acid solution
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Equation:
acid + acid = acid
0.30*150 + 1*x = 0.40(150+x)
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30*150 + 100x = 40*150 + 40x
60x = 10*150
x = (1/6)150
x = 25 mm (amt of pure acid needed)
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Cheers,
Stan H.
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