SOLUTION: A basket contains 7 green pears and 4 brown pears. One pear is selected at random and is not
replaced. A second pear is then selected at random. What is the probability that the
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-> SOLUTION: A basket contains 7 green pears and 4 brown pears. One pear is selected at random and is not
replaced. A second pear is then selected at random. What is the probability that the
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Question 893003: A basket contains 7 green pears and 4 brown pears. One pear is selected at random and is not
replaced. A second pear is then selected at random. What is the probability that the first pear is
brown and the second pair is green?
You can put this solution on YOUR website! A basket contains 7 green pears and 4 brown pears. One pear is selected at random and is not replaced. A second pear is then selected at random.
What is the probability that the first pear is brown and the second pair is green?
Ans: (4/11)(7/10) = 14/55
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Cheers,
Stan H.
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