SOLUTION: Two consecutive even integers such that three times the smaller one exceeds two times the larger one by 7

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Question 892849: Two consecutive even integers such that three times the smaller one exceeds two times the larger one by 7
Found 2 solutions by josgarithmetic, richwmiller:
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
You have 2n and 2n+2, the consecutive even integers. You want to find the "is" for the description so you know what to equate.

three times the smaller one, 3%282n%29;

exceeds two times the larger one by 7, "exceeds... by 7";
2%282n%2B2%29%2B7.

The human subject+verb situation is, FirstDescribedNumber exceeds.

The whole description starts as highlight%283%282n%29=2%282n%2B2%29%2B7%29.
Something is wrong with your problem description.
{{6n=4n+4+7}}}
2n=11
highlight_green%28n=11%2F2%29
-
First Number, 2n=2%2811%2F2%29=highlight%2811%29
Second Number, 2n%2B2=11%2B2=highlight%2813%29

The problem description is wrong.

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
3*2n=2*(2n+2)+7
6n=4n+4+7
2n=11
2n+2=13
The numbers are 11 and 13
But they are not even.
check
3*11=2*13+7
33=26+7
33=33
ok
There was no need in this case to use 2n and 2n+2
n and n+2 will do nicely
3*n=2(n+2)+7
3n=2n+4+7
n=11
n+2=13
unfortunately the answers are odd and even answers don't exist