SOLUTION: A radiator contains 8 liters of a 25% antifreeze solution. How much should be drained and replaced with pure antifreeze to produce a 66% antifreeze solution? (Round your answer to
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Question 892529: A radiator contains 8 liters of a 25% antifreeze solution. How much should be drained and replaced with pure antifreeze to produce a 66% antifreeze solution? (Round your answer to two decimal places.) Answer by robertb(5830) (Show Source):
You can put this solution on YOUR website! Let x = the # of liters to be drained and replaced.
After drainage, there is 8 - x liters left, with 25% antifreeze. The amount x liters is 100% antifreeze. The resulting 8 liters of solution has 66% antifreeze.
Hence 0.25*(8 - x) +1.00x = 0.66*8
==> 2- 0.25x + x = 5.28
==> 0.75x = 3.28
==> x = 3.28/0.75
+==> x = 4.37 liters of pure antrifreeze
