SOLUTION: divide: p^2+4p-5/p^2+7p+10 × p+4/p-1 a. 2 b. p+2 c. p+4/p+2 d. p+2/p+4

Algebra ->  Rational-functions -> SOLUTION: divide: p^2+4p-5/p^2+7p+10 × p+4/p-1 a. 2 b. p+2 c. p+4/p+2 d. p+2/p+4      Log On


   

Question 89248: divide: p^2+4p-5/p^2+7p+10 × p+4/p-1
a. 2
b. p+2
c. p+4/p+2
d. p+2/p+4
Answer by malakumar_kos@yahoo.com(315) About Me  (Show Source):
You can put this solution on YOUR website!

divide: p^2+4p-5/p^2+7p+10 × p+4/p-1
Factorise p^2+4p-5 = p^2+5p-p-5 = p(p+5)-1(p+5) = (p+5).(p-1)

p^2+7p+10 = p^2+5p+2p+10 = p(p+5)+2(p+5) = (p+5).(p+2)
Therefore p^2+4p-5/p^2+7p+10 x p+4/p-1 = (p+5).(p-1).(p+4)/(p+5).(p+2).(p-1)
= (p+4)/(p+2)