SOLUTION: the perimeter of a rectangle is 88 inches. if the length of the rectangle is 8 inches more than 3 times the width, find the dimensions

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Question 892478: the perimeter of a rectangle is 88 inches. if the length of the rectangle is 8 inches more than 3 times the width, find the dimensions
Answer by algebrahouse.com(1659) About Me  (Show Source):
You can put this solution on YOUR website!
w = width
3w + 8 = length {lenght is 8 more than 3 times width}

Perimeter of a rectangle = 2(width) + 2(length)

2w + 2(3w + 8) = 88 {substituted into perimeter formula}
2w + 6w + 16 = 88 {used distributive property}
8w + 16 = 88 {combined like terms}
8w = 72 {subtracted 16 from each side}
w = 9 {divided each side by 8}
3w + 8 = 35 {substituted 9, in for w, into 3w + 8}

width = 9 inches
length = 35 inches

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