SOLUTION: Sketch the parabola y = -x^2 + 10x - 16 by finding only the x and y intercepts, the line of symmetry and the vertex.

Algebra ->  Trigonometry-basics -> SOLUTION: Sketch the parabola y = -x^2 + 10x - 16 by finding only the x and y intercepts, the line of symmetry and the vertex.      Log On


   

Question 892254: Sketch the parabola y = -x^2 + 10x - 16 by finding only the x and y intercepts, the line of symmetry and the vertex.
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
The easy way for this one is factoring.

y=-x%5E2%2B10x-16
y=-1%28x%5E2-10x%2B16%29
y=-1%28x-2%29%28x-8%29

Zeros are at 2 and 8.
Line of symmetry is in the exact middle of those, at x=5.
The vertex is a maximum, at y=-1%285-2%29%285-8%29=-1%283%29%28-3%29=9 for the point (5,9).