SOLUTION: Find the error in the following proof that 1=0
Suppose a=b
A-b+b=b
A-b+b/a-b =b/a-b
A-b/a-b + b/a-b = b/a-b
1+ b/a-b = b/a-b
Now subtract b/a-b from both sides and get 1=
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Expressions-with-variables
-> SOLUTION: Find the error in the following proof that 1=0
Suppose a=b
A-b+b=b
A-b+b/a-b =b/a-b
A-b/a-b + b/a-b = b/a-b
1+ b/a-b = b/a-b
Now subtract b/a-b from both sides and get 1=
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Question 892128: Find the error in the following proof that 1=0
Suppose a=b
A-b+b=b
A-b+b/a-b =b/a-b
A-b/a-b + b/a-b = b/a-b
1+ b/a-b = b/a-b
Now subtract b/a-b from both sides and get 1=0 Answer by robertb(5830) (Show Source):
You can put this solution on YOUR website! Since a = b, one cannot divide by a - b, because a - b = 0. This also makes an invalid term, thus cannot be subtracted from both sides of the "equation".
