Question 891700: log8-logx-log(x-2)=-1
Answer by LinnW(1048)   (Show Source):
You can put this solution on YOUR website! log8-logx-log(x-2)=-1
add -log8 to each side
-logx - log(x-2) = -1 -log8
multiply each side by -1
logx + log(x-2) = 1 + log8
Assuming log means log base 10
log(x) + log(x-2) = log(10) + log(8)
log(x(x-2)) = log(10*8)
log(x(x-2)) = log(80)
x(x-2) = 80
x^2 -2x = 80
x^2 -2x -80 = 0
(x-10)(x+8) = 0
so x = 10
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