SOLUTION: How many gallons of 30% alcohol must be mixed with 60 gallons of 14% alcohol to obtain a solution that is 20% alcohol.

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Question 891570: How many gallons of 30% alcohol must be mixed with 60 gallons of 14% alcohol to obtain a solution that is 20% alcohol.
Found 2 solutions by louiramirez229@yahoo.com, josmiceli:
Answer by louiramirez229@yahoo.com(1) About Me  (Show Source):
You can put this solution on YOUR website!
How many gallons of 30% alcohol must be mixed with 60 gallons of 14% alcohol to obtain a solution that is 20% alcohol.

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +x+ = gallons of 30% alcohol needed
+.14%2A60+=+8.4+ gallons of alcohol in 14% solution
-------------------
+%28+.3x+%2B+8.4+%29+%2F+%28+x+%2B+60+%29+=+.2+
+.3x+%2B+8.4+=+.2%2A%28+x+%2B+60+%29+
+.3x+%2B+8.4+=+.2x+%2B+12+
+.1x+=+3.6+
+x+=+36+
36 gallons of 30% alcohol are needed
check:
+%28+.3x+%2B+8.4+%29+%2F+%28+x+%2B+60+%29+=+.2+
+%28+.3%2A36+%2B+8.4+%29+%2F+%28+36+%2B+60+%29+=+.2+
+%28+10.8+%2B+8.4+%29+%2F+96+=+.2+
+19.2+=+.2%2A96+
+19.2+=+19.2+
OK