Question 891419: Find four consecutive odd integers with a sum of 464.
Answer by JulietG(1812)   (Show Source):
You can put this solution on YOUR website! A + B + C + D = 464
B = A+2 (consecutive, odd)
C = A+4
D = A+6
Substitute the known values into the first equation
A+B+C+D = 464
A + (A+2) + (A+4) + (A+6) = 464
Add
4A + 12 = 464
Subtract 12 from each side
4A = 452
Divide each side by 4
A = 113
Therefore, B =115, C=117, D=119
113+115+117+119 = 464
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