SOLUTION: solve 4x^2-8x+3=5

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Question 89136: solve
4x^2-8x+3=5
Answer by checkley75(3666) About Me  (Show Source):
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4X^2-8X+3=5
4X^2-8X+3-5=0
4X^2-8X-2=0
USING THE QUADRATIC EQUATION WE GET:x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
X=(8+-SQRT{-8^2-4*4*-2])/2*4
X=(8+-SQRT[64+32])/8
X=(8+-SQRT96)/8
X=(8+-9.7979)/8
X=(8+9.7979)/2
X=17.7979/8
X=2.22 ANSWER.
X=(8-9.7979)/8
X=-1.7979/8
X=-.22 ANSWER.