SOLUTION: find four consecutive even integers such that the sum of the second integer and the fourth integer is one and a half times the sum of the first and third integer
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Question 891072: find four consecutive even integers such that the sum of the second integer and the fourth integer is one and a half times the sum of the first and third integer Answer by JulietG(1812) (Show Source):
You can put this solution on YOUR website! B = A+2
C = A+4
D = A+6
where A is the smallest of the integers
B + D = 1.5(A + C)
Substitute the known values from the first equations into the last.
B+D = 1.5(A+C)
(A+2)+(A+6)=1.5(A+[A+4])
2A+8=1.5(2A+4)
Distribute
2A+8=3A+6
Subtract 6 from each side
2A+2=3A
Subtract 2A from each side
2=A
.
If A is 2, then B is 4, C is 6, and D is 8
Let's see if that works.
"The sum of the second integer and the fourth integer is one and a half times the sum of the first and third integer."
4+8 = 1.5(2+6)
12=1.5(8)
12=12
Success!
