SOLUTION: andy has $2.40 in nickels and dimes. Barry has $5.50 in dimes and quarters. Barry has as many nickels as andy has nickels, and he also has as many quarters as andy has dimes. how m

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: andy has $2.40 in nickels and dimes. Barry has $5.50 in dimes and quarters. Barry has as many nickels as andy has nickels, and he also has as many quarters as andy has dimes. how m      Log On

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Question 891000: andy has $2.40 in nickels and dimes. Barry has $5.50 in dimes and quarters. Barry has as many nickels as andy has nickels, and he also has as many quarters as andy has dimes. how many nickels and dimes does andy have
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +d%5Bb%5D+ = the number of dimes Barry has
Let +q%5Bb%5D+ = the number of quarters Barry has
Let +n%5Ba%5D+ = the number of nickels Andy has
Let +d%5Ba%5D+ = the number of dimes Andy has
--------------------------------------------
(1) +10d%5Bb%5D+%2B+25q%5Bb%5D+=+550+ ( in cents )
(2) +10d%5Ba%5D+%2B+5n%5Ba%5D+=+240+
(3) +n%5Bb%5D+=+n%5Ba%5D+
(4) +q%5Bb%5D+=+d%5Ba%5D+
--------------------
There are 4 equations and 4 unknowns,
so it's solvable
Substitute (4) into (2)
(2) +10d%5Ba%5D+%2B+5n%5Ba%5D+=+240+
(2) +10q%5Bb%5D+%2B+5n%5Ba%5D+=+240+
Substitute (3) into (2)
(2) +10q%5Bb%5D+%2B+5n%5Ba%5D+=+240+
(2) +10q%5Bb%5D+%2B+5n%5Bb%5D+=+240+
(2) +5n%5Bb%5D+%2B+10q%5Bb%5D+=+240+
------------------------------
Multiply both sides of (2) by +2+
and subtract (2) from (1)
(1) +10d%5Bb%5D+%2B+25q%5Bb%5D+=+550+
(2) +-10d%5Bb%5D+-+20q%5Bb%5D+=+-480+
-------------------------------
+5q%5Bb%5D+=+70+
+q%5Bb%5D+=+14+
and, since
(4) +q%5Bb%5D+=+d%5Ba%5D+
(4) +d%5Ba%5D+=+14+
------------------
Back to (1)
(1) +10d%5Bb%5D+%2B+25q%5Bb%5D+=+550+
(1) +10d%5Bb%5D+%2B+25%2A14+=+550+
(1) +10d%5Bb%5D+=+550+-+350+
(1) +10d%5Bb%5D+=+200+
(1) +d%5Bb%5D+=+20+
------------------
Back to (2)
(2) +10d%5Ba%5D+%2B+5n%5Ba%5D+=+240+
(2) +10%2A14+%2B+5n%5Ba%5D+=+240+
(2) +5n%5Ba%5D+=+240+-+140+
(2) +n%5Ba%5D+=+100%2F5+
(2) +n%5Ba%5D+=+20+
Andy has 20 nickels and 14 dimes
--------------------------------
check:
(1) +10d%5Bb%5D+%2B+25q%5Bb%5D+=+550+
(1) +10%2A20+%2B+25%2A14+=+550+
(1) +200+%2B+350+=+550+
(1) +550+=+550+
OK
You can check the other equations