Question 890989: A deck of playing cards consists of 52 cards divided into 4 "suits": hearts, clubs, spades, and diamonds. Each suit consists of 13 cards with different values: 9 "number cards (numbered 2, 3, 4, 5, 6, 7, 8, 9, and 10), 3 "face" cards (Jack, Queen, and King) and an Ace. A card is chosen at random, its value is recorded, and it is returned to the deck. Then a second card is chosen at random. What is the probability that the first card is the 7 of Clubs and the second card is a Queen of Hearts?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A deck of playing cards consists of 52 cards divided into 4 "suits": hearts, clubs, spades, and diamonds. Each suit consists of 13 cards with different values: 9 "number cards (numbered 2, 3, 4, 5, 6, 7, 8, 9, and 10), 3 "face" cards (Jack, Queen, and King) and an Ace. A card is chosen at random, its value is recorded, and it is returned to the deck. Then a second card is chosen at random. What is the probability that the first card is the 7 of Clubs and the second card is a Queen of Hearts?
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P(7C AND QH) = 1/52 * 1/52 = (1/52)^2
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Cheers,
Stan H.
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