Question 890977: The legs of a right triangle have length x and 3x-5 and the hypotenuse has length x+2. Find the value of x. Answer by dkppathak(439) (Show Source):
You can put this solution on YOUR website! The legs of a right triangle have length x and 3x-5 and the hypotenuse has length x+2. Find the value of x.
(x+2)^2= X^2 +(3x-5)^2
X^2+4+4X=X^2+9X^2 +25-30X
10X^2-30X+25-X^2-4X-4=0
9X^2-34X+21=0
9X^2-27X-7X+21=0
(9X-7)(x-3)=0
x=7/9 or x=3
