SOLUTION: 1.Amanda has a piggy bank filled with P1.00- coins. She took out 15 coins less than half the number of coins on Monday. On Tuesday, she took half of the remainder plus 4 coins. She

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Question 890603: 1.Amanda has a piggy bank filled with P1.00- coins. She took out 15 coins less than half the number of coins on Monday. On Tuesday, she took half of the remainder plus 4 coins. She acidentally broke her piggybank on Wednesday and counted there were 12 coins. How many coins were there in the piggybank originally?
Answer by ankor@dixie-net.com(22740) (Show Source):
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1.Amanda has a piggy bank filled with P1.00- coins.
let n = original number coins
She took out 15 coins less than half the number of coins on Monday.
n - (.5n-15)
n - .5n + 15
.5n + 15 remain
:
On Tuesday, she took half of the remainder plus 4 coins.
She accidentally broke her piggy-bank on Wednesday and counted there were 12 coins.
(.5n+15) - (.5(.5n+15)+ 4) = 12
(.5n+15) - (.25n + 7.5 + 4) = 12
(.5n+15) - (.25n + 11.5) = 12
.5n + 15 -.25n - 11.5 = 12
.5n - .25n + 15 - 11.5 = 12
.25n + 3.5 = 12
.25n = 12 - 3.5
.25n = 8.5
n = 8.5/.25
n = 34 coins originally