SOLUTION: Mr Tong has some guavas and papayas in two crates. In crate A, the number of guavas and papayas are in the ratio of 5:3. In crate B, the number of guavas is 4/9 the number of papa

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: Mr Tong has some guavas and papayas in two crates. In crate A, the number of guavas and papayas are in the ratio of 5:3. In crate B, the number of guavas is 4/9 the number of papa      Log On

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Question 890566: Mr Tong has some guavas and papayas in two crates. In crate A, the number of guavas and papayas are in the ratio of 5:3. In crate B, the number of guavas is 4/9 the number of papayas. Mr Tong transfers half of the guavas from crate A to crate B. The number of fruits in crate A becomes 308 and the ratio of the number of guavas to the number of papayas in crate B becomes 5:6.
(a) How many guavas have been transferred from crate A to crate B?
(b) What is the number of fruits in crate B after the transfer?

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +g%5BA%5D+ = number of guavas in crate A
Let +p%5BA%5D+= number of papayas in crate A
Let +g%5BB%5D+ = number of guavas in crate B
Let +p%5BB%5D+= number of papayas in crate B
----------------------------------------
(1) +g%5BA%5D+%2F+p%5BA%5D+=+5%2F3+
(2) +g%5BB%5D+=+%284%2F9%29%2Ap%5BB%5D+
(2) +g%5BB%5D+%2F+p%5BB%5D+=+4%2F9+
-------------------------
After transfer:
+g%5BA%5D+%2F+2+ guavas in crate A
+g%5BA%5D+%2F+2+%2B+g%5BB%5D+ guavas in crate B
------------------------------------
+308+ fruits in crate A
(3) +g%5BA%5D+%2F+2+%2B+p%5BA%5D+=+308+
-------------------------------
(4) +%28+g%5BA%5D+%2F+2+%2B+g%5BB%5D+%29+%2F+p%5BB%5D+=+5%2F6+
-------------------------------
(3) +g%5BA%5D+%2F+2+%2B+p%5BA%5D+=+308+
and, from (1):
(1) +g%5BA%5D+%2F+p%5BA%5D+=+5%2F3+
(1) +g%5BA%5D+=+%285%2F3%29%2Ap%5BA%5D+
(1) +p%5BA%5D+=+%28+3%2F5+%29%2Ag%5BA%5D+
By substitution:
(3) +g%5BA%5D+%2F+2+%2B+%28+3%2F5+%29%2Ag%5BA%5D+=+308+
(3) +g%5BA%5D+%2A%28+1%2F2+%2B+3%2F5+%29+=+308+
(3) +g%5BA%5D%2A%28+11%2F10+%29+=+308+
(3) +g%5BA%5D+=+%28+10%2F11+%29%2A308+
(3) +g%5BA%5D+=+280+
---------------------
(2) +g%5BB%5D+%2F+p%5BB%5D+=+4%2F9+
(2) +p%5BB%5D+=+%289%2F4%29%2Ag%5BB%5D+
And, after transfer:
(4) +%28%28+g%5BA%5D+%2F+2+%2B+g%5BB%5D+%29%29+%2F+p%5BB%5D+=+5%2F6+
(4) +%28%28+280+%2F+2+%2B+g%5BB%5D+%29%29+%2F+p%5BB%5D+=+5%2F6+
(4) +%28%28+140+%2B+g%5BB%5D+%29%29+%2F+p%5BB%5D+=+5%2F6+
(4) +140+%2B+g%5BB%5D+=+%285%2F6%29%2Ap%5BB%5D+
Substitute (2) into (4)
(4) +140+%2B+g%5BB%5D+=+%285%2F6%29%2A%289%2F4%29%2Ag%5BB%5D+
(4) +140+%2B+g%5BB%5D+=+%28+15%2F8+%29%2Ag%5BB%5D+
(4) +%28+7%2F8+%29%2Ag%5BB%5D+=+140+
(4) +g%5BB%5D+=+%288%2F7%29%2A140+
(4) +g%5BB%5D+=+160+
--------------------
+g%5BA%5D+%2F+2+=+280%2F2+
+g%5BA%5D+%2F+2+=+140+
-------------------
(a) 140 guavas were transferred to crate B
-------------------
(4) +%28+g%5BA%5D+%2F+2+%2B+g%5BB%5D+%29+%2F+p%5BB%5D+=+5%2F6+
(4) +%28+280+%2F+2+%2B+160+%29+%2F+p%5BB%5D+=+5%2F6+
(4) +%28+140+%2B+160+%29+%2F+p%5BB%5D+=+5%2F6+
(4) +p%5BB%5D+=+300%2A%28+6%2F5+%29+
(4) +p%5BB%5D+=+360+
---------------------
After the transfer,
+g%5BA%5D+%2F+2+%2B+g%5BB%5D+%2B+p%5BB%5D+=+140+%2B+160+%2B+360+
+g%5BA%5D+%2F+2+%2B+g%5BB%5D+%2B+p%5BB%5D+=+660+
--------------------------------
(b) There are 660 fruits in crate B
check:
(1) +g%5BA%5D+%2F+p%5BA%5D+=+5%2F3+
(1) +p%5BA%5D+=+%283%2F5%29%2Ag%5BA%5D+
(1) +p%5BA%5D+=+%283%2F5%29%2A280+
(1) +p%5BA%5D+=+168+
and
(3) +g%5BA%5D+%2F+2+%2B+p%5BA%5D+=+308+
(3) +140+%2B+168+=+308+
(3) +308+=+308+
OK