SOLUTION: two cyclist are 25 mi apart and traveling toward each other.
One cyclist is traveling at 2/3 the rate of the other.They pass in 2h.Find rate
of each cyclist.
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-> SOLUTION: two cyclist are 25 mi apart and traveling toward each other.
One cyclist is traveling at 2/3 the rate of the other.They pass in 2h.Find rate
of each cyclist.
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Question 890540: two cyclist are 25 mi apart and traveling toward each other.
One cyclist is traveling at 2/3 the rate of the other.They pass in 2h.Find rate
of each cyclist. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! two cyclist are 25 mi apart and traveling toward each other.
One cyclist is traveling at 2/3 the rate of the other.
They pass in 2h.Find rate of each cyclist.
:
Let s = the speed of the faster cyclist
then s = the speed of the slower
:
Since they are going towards each other, we can solve this by adding their speeds
1s + s = s, the combined speed of the two bikes
:
dist = time * speed
:
2*s = 25 s = 25
multiply both sides by 3
10s = 75
s = 75/10
s = 7.5 mph, speed of the faster
then *7.5 = 5 mph the speed of the slower
:
:
Check this find the distance each traveled
2*7.5 = 15 mi
2 * 5 = 10 mi
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total dist: 25 mi
