SOLUTION: one seventh of the sum of 2 numbers is 6, and 4 times their difference is 64. find these numbers

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Question 890537: one seventh of the sum of 2 numbers is 6, and 4 times their difference is 64. find these numbers
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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one seventh of the sum of 2 numbers is 6, and 4 times their difference is 64. find these numbers
:
let the two numbers be a & b
Write an equation for each statement, simplify as much as possible.
:
"one seventh of the sum of 2 numbers is 6,"
1%2F7(a+b) = 6
multiply both sides by 7
a + b = 42
:
"and 4 times their difference is 64."
4(a-b) = 64
divide both sides by 4
a - b = 16
:
Add the two simplified equations
a + b = 42
a - b = 16
-------------adding eliminates b, find a
2a = 58
a = 58/2
a = 29
Find b
29 + b = 42
b = 42 - 29
b = 13
:
these two numbers: 29 and 13
:
:
Check this in the 2nd statement
4(29-13) = 64
4(16) = 64