Question 890501: A person wants to purchase two types of items, A and B, from a shop. She has $200 to spend, and she has to purchase at least 10 items. If the price of one unit of each A and B is $10 and $30, respectively, represent this problem graphically.
Found 2 solutions by JulietG, MathTherapy:
Answer by JulietG(1812)   (Show Source):
You can put this solution on YOUR website! Use a column, and list the whole numbers that make the equation $200
A10 + B30 = 200
When A is ..... B is ....
5, 5 ($10*5 = 50 and $30*5 = 150, making $200 total, and purchasing at least 10 items)
8, 4
11, 3
14, 2
17, 1
20, 0
Plot those points to draw your line on the graph.
Answer by MathTherapy(10555)  (Show Source):
You can put this solution on YOUR website!
A person wants to purchase two types of items, A and B, from a shop. She has $200 to spend, and she has to purchase at least 10 items. If the price of one unit of each A and B is $10 and $30, respectively, represent this problem graphically.
Let items A and B, be x, and y, respectively
Then we get:  ------- (i)
Also, 10x + 30y = 200_____10(x + 3y) = 10(20)___x + 3y = 20 ----- (ii)
Graph inequality and equation and shade the necessary sections.
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