SOLUTION: The length of a rectangle is 1 cm less than twice the width. Find the length and width if the perimeter is 22 cm

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Question 890414: The length of a rectangle is 1 cm less than twice the width. Find the length and width if the perimeter is 22 cm
Answer by algebrahouse.com(1659) About Me  (Show Source):
You can put this solution on YOUR website!
x = width
2x - 1 = length {length is 1 less than twice width}

Perimeter of a rectangle = 2(width) + 2(length)

2x + 2(2x - 1) = 22 {perimeter is 2(width) + 2(length)}
2x + 4x - 2 = 22 {used distributive property}
6x - 2 = 22 {combined like terms}
6x = 24 {added 2 to each side}
x = 4 {divided each side by 6}
2x - 1 = 7 {substituted 4, in for x, into 2x - 1}

width = 4 cm
length = 7 cm

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