Question 890404: Three intergers are in A.P. The difference between first and last terms is 4 and their product is 60. what are the integers
Answer by CubeyThePenguin(3113) (Show Source):
You can put this solution on YOUR website! AP = arithmetic progression
a = first term
d = common difference
a, a+d, a+2d
(a+2d) - a = 4 ---> d = 4/2 = 2
a(a+4) = 60
a^2 + 4a - 60 = 0
(a + 10)(a - 6) = 0
The integers could be {-10, -8, -6} or {6, 8, 10.}
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