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| Question 890363:  find all values of a in [0 degrees,360 degrees) that satisfy the given equation.
 sec3a=2
 thank you !
 Answer by Alan3354(69443)
      (Show Source): 
You can put this solution on YOUR website! sec(3a) = 2 cos(3a) = 1/2
 3a = 60, 300, 420, 660, 780, 1020 degs
 (Or, 3a = 60 + n*360, n = 0,1,2,3... degs)
 (Or, 3a = 300 + n*360, n = 0,1,2,3... degs)
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 a = 20, 100, 140, 220, 260, 340 degs
 
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