SOLUTION: Jay jay rode his bicycle against the wind for 1 hour and traveled 15 km. then he traveled back the same distance with the wind in 36 minutes, what was the rate of the wind?
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Question 890301: Jay jay rode his bicycle against the wind for 1 hour and traveled 15 km. then he traveled back the same distance with the wind in 36 minutes, what was the rate of the wind? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Jay jay rode his bicycle against the wind for 1 hour and traveled 15 km.
then he traveled back the same distance with the wind in 36 minutes,
what was the rate of the wind?
:
Change 36 to hrs, 36/60 = .6 hrs
:
Let b = bike speed in still air
let w = rate of the the wind
then
(b-w) = effective speed against the wind
(b+w) = effective speed with the wind
:
Write a distance equation for each way, dist = time * speed
1(b-w) = 15
b = w + 15
and
.6(b+w) = 15
replace b = (w+15)
.6((w+15)+ w) = 15
.6(2w+15) = 15
1.2w + 9 = 15
1.2w = 15 - 9
1.2w = 6
w = 6/1.2
w = 5 km/h is the wind
