SOLUTION: three consecutive integers such that five times the middle integer is twelve more than twice th sum of the first and third.
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Question 890292: three consecutive integers such that five times the middle integer is twelve more than twice th sum of the first and third. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! three consecutive integers such that five times the middle integer is twelve more than twice th sum of the first and third.
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1st: x-1
2nd: x
3rd: x+1
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Equation:
5x = 2(x-1+x+1)+12
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5x = 2x + 12
3x = 12
x = 4
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1st: x-1 = 3
2nd: x = 4
3rd: x+1 = 5
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Cheers,
Stan H.
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