SOLUTION: 7-(-y-5)= 2(y+3)-6(y+1)
want to know if I should distributive only the neg. sign to the -y or the 7
at the beginning of the problem, I came up with 5 over 11y
but text book s
Algebra ->
Distributive-associative-commutative-properties
-> SOLUTION: 7-(-y-5)= 2(y+3)-6(y+1)
want to know if I should distributive only the neg. sign to the -y or the 7
at the beginning of the problem, I came up with 5 over 11y
but text book s
Log On
want to know if I should distributive only the neg. sign to the -y or the 7
at the beginning of the problem, I came up with 5 over 11y
but text book states -12 over 5 Found 2 solutions by malakumar_kos@yahoo.com, praseenakos@yahoo.com:Answer by malakumar_kos@yahoo.com(315) (Show Source):
You can put this solution on YOUR website!
7-(-y-5)= 2(y+3)-6(y+1)
want to know if I should distributive only the neg. sign to the -y or the 7
at the beginning of the problem, I came up with 5 over 11y
but text book states -12 over 5
The - sign should be distributive only to -y &-5 and not 7
The solution goes like this : 7-(-y-5) = 2(y+3)-6(y+1)
7+y+5 = 2y+6-6y-6
y+12 = -4y+0
y+4y = -12
5y = -12 or y = -12/5
want to know if I should distributive only the neg. sign to the -y or the 7
at the beginning of the problem, I came up with 5 over 11y
but text book states -12 over 5
Answer:
7-(-y-5)= 2(y+3)-6(y+1)
For solving this you have to remove the parenthesis first.
Here negative sign is distributive only to -y and -5
Hope you are familiar with multiplication of signs...
(