Question 890159: The ages of three brothers, A,B and C, add up to 22. A is 2.5 times older than C. When A was as old as B is today, B is 3 times as old as C. Find their ages.
Answer by robertb(5830)   (Show Source):
You can put this solution on YOUR website! A + B + C = 22, and  , from the given.
Now A - B = difference between the ages of A and B.
Hence, A - B years ago,
B - (A - B) = 3[C - (A - B)], from the third sentence.
==> 2A = B + 3C, after simplifying the last equation.
==> 5C = B + 3C, after putting in
==> B = 2C
Then direct substitution gives
==>  , or
C = 4 years old,
==> B = 8 years old, and
 years old
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