Bring the first two terms to higher-terms according to denominator x.
There, you want to use the NUMERATOR to see how it is related to zero; the denominator will not really be relevant, except that the solution for x must EXCLUDE x=0.
The important critical points are at x being the zeros of the numerator.
The inequality will be satisfied for or for ----
The possibility of x=0 will no longer be necessary to consider since it is not within the domain for this inequality.
........ ------ Multiplying both sides be LCD, x
2x + 1 = 0 OR x - 2 = 0 ------- Converting inequality to equality
2x = - 1 OR x = 0 + 2 OR x = 2
Critical points are , , since , and .
Therefore the four intervals to check are: , , , and .
Intervals that satisfy INEQUALITY: and
(